4m^2-7m-1=0

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Solution for 4m^2-7m-1=0 equation: 



4m^2-7m-1=0

a = 4; b = -7; c = -1;
Δ = b2-4ac
Δ = -72-4·4·(-1)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{65}}{2*4}=\frac{7-\sqrt{65}}{8}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{65}}{2*4}=\frac{7+\sqrt{65}}{8}
$

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